#include#includeusing namespace std;const int SIZE = 100;int main(){\tint n,i,sum,x,a[SIZE]; \tcin>>n;\tmemset(a,0,sizeof(a)); \tfor(i=1;i<=n;i ){\t\tcin>>x;\t\ta[x] ;\t }\ti=0;\tsum=0;\twhile(sum<(n/2 1)){\t\ti ;\t\tsum =a[i]; \t} \tcout<输入:
11
4 5 6 6 4 3 3 2 3 2 1
输出:
发表评论 取消回复